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Redox Reactions — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryRedox Reactions3 Marks
Question
Balance the following equations by the oxidation number method.
$\text{I}_2+\text{S}_2\text{O}^{2-}_3\xrightarrow{ \ \ \ \ \ \ }\text{I}^-+\text{S}_4\text{O}^{2-}_6$
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Answer

$\stackrel{0}{\text{I}_2}+\stackrel{+2 \ \ \ \ }{\text{S}_2}\stackrel{-2 \ \ \ \ \ }{\text{O}^{2-}_3}\xrightarrow{ \ \ \ \ \ \ \ }\stackrel{-1 \ \ \ \ }{\text{I}^-}+\stackrel{+2.5}{\text{S}_4}\text{O}^{2-}_6$
Total increase in O.N. = 0.5 × 4 = 2
Total decrease in O.N. = 1 × 2 =2
To equalize O.N. multiply $\text{S}_2\text{O}^{2-}_3$ and $\text{I}^-$ by 2.
$\text{I}_2+2\text{S}_2\text{O}^{2-}_3\xrightarrow{ \ \ \ \ \ \ \ }2\text{I}^-+\text{S}_4\text{O}^{2-}_6$

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