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Question

Balance the following unbalanced equation by ion electron method (half reaction method). H _2 O _ 2( aq ) + ClO _ 4( aq ) ^ - ClO _ 2( aq ) ^ - + O _ 2( g )

Accepted Answer

Balance the following unbalanced equation by ion electron method (half reaction method).
$
H _2 O _{2( aq )}+ ClO _{4( aq )}^{-} \longrightarrow ClO _{2( aq )}^{-}+ O _{2( g )}
$

Step 2: Balance the atoms except $O$ and $H$ in each half equation. Balance the half equation for $O$ atoms by adding $H _2 O$ to the side with less $O$ atoms.
Hence, add $2 H _2 O$ to the right side of reduction half equation and none to the oxidation half equation
Oxidation: $H _2 O _{2(\text { (aq) }} \longrightarrow O _{2( g )}$
Reduction: $ClO _{4( aq )}^{-} \longrightarrow ClO _{2( aq )}^{-}+2 H _2 O _{(l)}$
Step 3: Balance $H$ atoms by adding $H ^{+}$ions to the side with less $H$. Hence add $2 H ^{+}$ ions to the right side of oxidation half equation and $4 H ^{+}$ions to the left side of reduction half equation.
Oxidation: $H _2 O _{2(\text { (aq) }} \longrightarrow O _{2( g )}+2 H _{( aq )}^{+}$
Reduction: $ClO _{4( aq )}^{-}+4 H _{( aq )}^{+} \longrightarrow ClO _{2( aq )}^{-}+2 H _2 O _{( f }$
Step 4: Add 2 electrons to the right side of oxidation half equation and 4 electrons to the left side of reduction half equation to balance the charges.
Oxidation: $H _2 O _{2(\text { aq })} \longrightarrow O _{2( g )}+2 H _{( aq )}^{+}+2 e ^{-}$
Reduction: $ClO _{4(\text { (aq) }}^{-}+4 H _{( aq )}^{+}+4 e ^{-} \longrightarrow ClO _{2(\text { (aq) }}^{-}+2 H _2 O _{(l)}$
Step 5: Multiply oxidation half equation by 2 to equalize the number of electrons and then add two half equations. Oxidation: $2 H _2 O _{2(\text { (aq) }} \longrightarrow 2 O _{2( g )}+4 H _{( aq )}^{+}+4 e ^{-}$
Reduction: $ClO _{4(\text { (aq) }}^{-}+4 H _{(\text {(aq) }}^{+}+4 e ^{-} \longrightarrow ClO _{2(\text { (aq) }}^{-}+2 H _2 O _{( l )}$ Add two half equations: $ \left.2 H _2 O _{2(\text { aq })}+ ClO _{4( aq )}^{-}\right) 2 O _{2( g )}+ ClO _{2( aq )}^{-}+2 H _2 O _{(l)} $ This equation is balanced in terms of atoms and charges. Hence, balanced equation: $2 H _2 O _{2(\text { (aq) }}+ C l O _{4(\text { (aq) }}^{-} \longrightarrow 2 O _{2( g )}+ C O O _{2( aq )}^{-}+ 2 H _2 O _{(l)}$

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