\(\left[\mathrm{H}^{+}\right]=10^{-12}\)
\(\left[\mathrm{OH}^{-}\right]=\frac{10^{-14}}{10^{-12}}=10^{-2}\)
\(\mathrm{Ba}(\mathrm{OH})_{2} \rightleftharpoons \mathrm{Ba}^{2+}+2 \mathrm{OH}^{-}\)
\(\quad \quad \quad \quad \quad \quad s \quad \quad \quad 2 s\)
\(2 s=10^{-2} \Rightarrow s=\frac{10^{-2}}{2}\)
\(K_{s p}=(s)(2 s)^{2}=4 s^{3}\)
\(=4 \times\left(\frac{10^{-2}}{2}\right)^{3}=\frac{4}{8} \times 10^{-6}\)
\(=5 \times 10^{-7}\)