$y  $ ના મોલ- અંશ ${X_B} = \frac{3}{{1 + 3}} = \frac{3}{4}$

${\text{P}}$ કુલ ${\text{ =  }}{{\text{p}}_{\text{A}}}^{\text{0}}{{\text{X}}_{\text{A}}}{\text{  +  }}{{\text{p}}_{\text{B}}}^{\text{0}}{{\text{X}}_{\text{B}}}\,$

$ \Rightarrow \,\,\,{\text{P}}$ કુલ $ = \frac{{{P_A}^0}}{4} + \frac{{{P_B}^0}}{5}$

$\therefore \,\,550 = \frac{{{p_A}^0 + 3p{B^0}}}{4}\,\,\,$

$\therefore \,\,\,{{P}^{0}}_{A}\text{+ 3}{{\text{p}}_{\text{B}}}^{\text{0}}\text{  =  550 }\times \,\,\text{4}\,\text{=}\,\text{2200}$ ............... $(1)$

$y $ નો $1 $  મોલ ઉમેરતા,  $\,{\text{P}}$ કુલ ${\text{ =  }}{{\text{p}}_{\text{A}}}^{\text{0}}{{\text{X}}_{\text{A}}}{\text{  +  }}{{\text{p}}_{\text{B}}}^{\text{0}}{{\text{X}}_{\text{B}}}\,$

$\therefore 560 = \frac{{{P_A}^0}}{5} + \frac{{4{p_B}^0}}{5}$

${X_A} = \frac{1}{{1 + 4}} = \frac{1}{5},\,\,\,\,\,\,{X_B} = \frac{4}{{1 + 4}} = \frac{4}{5}$

$\therefore {\text{ }}{{\text{p}}_{\text{A}}}^{\text{0}}{\text{  +  4}}{{\text{p}}_{\text{B}}}^{\text{0}}{\text{  =  560 }} \times {\text{ 5}}\,\,$

$\therefore \text{  }{{\text{p}}_{\text{A}}}^{\text{0}}\text{+ 4}-{{\text{p}}_{\text{B}}}^{\text{0}}\,\text{=}\,\,\text{2800}$   .............................. $(2)$

પરિણામ $(2)$  - પરિણામ $ (1)$  કરતાં

$\therefore \,\,{{\text{p}}_{\text{A}}}^0 + 4{p_B}^0\, - \,{p_A}^0 - 3{p_B}^0 = 2800 - 2200$

$\therefore {\text{  }}{{\text{p}}_{\text{B}}}^{\text{0}}{\text{  =  600}}$ મિમી

${\text{ }}\therefore {\text{ }}{{\text{p}}_{\text{A}}}^{\text{0}}{\text{  =  400 }}$ મિમી