MCQ
$\begin{array}{*{20}{c}}
  {Ph - C{H_2} - CH - C{H_3}\xrightarrow{{B{r_2}/hv}}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,} \\ 
  {D\,\,\,\,\,\,\,\,\,\,} 
\end{array}$

Product of the above reaction will be

  • Diastereomers
  • B
    Racemic mixture
  • C
    Meso
  • D
    Constitutional isomers

Answer

Correct option: A.
Diastereomers
a
$\begin{array}{*{20}{c}}
  {Ph - C{H_2} - CH - C{H_3}\xrightarrow{{B{r_2}/hv}}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,} \\ 
  {D\,\,\,\,\,\,\,\,\,\,} 
\end{array}$

$\begin{array}{*{20}{c}}
  {Ph - \mathop {{\text{ }}C}\limits^* H - \mathop {{\text{ }}C}\limits^* H - C{H_3}} \\ 
  {|{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,\,\,\,\,\,\,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} |{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} } \\ 
  {Br{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,{\mkern 1mu} {\mkern 1mu} \,\,\,\,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} D\,\,\,\,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} } 
\end{array}$

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