$\mathop {{H_3}C\mathop C\limits^ \ominus {H_2}}\limits_{(i)} \,,$$\mathop {{H_2}C = \mathop C\limits^ \ominus H}\limits_{(ii)} $ અને $\mathop {H - C \equiv \mathop C\limits^ \ominus }\limits_{(iii)} $
Among alkane, alkene and alkyne are most acidic and alkanes are least acidic, so the order of base strengths
alkane \(>\) alkene \(>\) alkyne
\(C H_{3} \stackrel{\ominus}{C} H_{2}>H_{2} C=\stackrel{\ominus}{C} H>H-C \equiv {C}^{\ominus}\)