So there are a total of 12 sigma bonds and 3 pi bonds in benzene. The carbon atoms are bonded through \(\mathrm{sp}^{2}-\mathrm{Sp}^{2}\) overlap while six \(\mathrm{C}-\mathrm{H}\) bond is formed by \(\mathrm{sp}^{2}-\mathrm{s}\) sigma bond.
Thus there is \(6 \mathrm{sp}^{2}-\mathrm{s}\) sigma bond.
$[$ આપેલ $: \sqrt{3}=1.73, \sqrt{2}=1.41]$