The resistance of a galvanometer is $50\,\Omega $ and it requires $2\,\mu A$ per two division deflection. The value of the shunt required in order to convert this galvanometer into ammeter of range $5\,A$ is (The number of divisions on the galvanometer scale on one side is $30$)
  • A$0.2\,\Omega $
  • B$0.002\,\Omega $
  • C$3 \times {10^{ - 4}}\,\Omega $
  • D$4 \times {10^{ - 6}}\,\Omega $
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