MCQ
Blood calcium level can be increased by the administration of
- AGlucogon
- BCalcitonin
- CThyroxine
- ✓Paratharmone
$B.$ Thyroxine is secreted from thyroid gland. It stimulates the consumption of oxygen by metabolically active tissues and also increases the oxidation of glucose in tissues.
$C.$ Parathormone is secreted from parathyroid gland and increases calcium reabsorption from the bones and causes mobilisation of calcium in the blood.
$D.$ Calcitonin is secreted from the $C-$cells of thyroid gland and acts on bone and kidneys to reduce blood calcium level. Hence, blood calcium level is increased by parathormone. So, the correct answer is $'Parathormone'$.
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$\xrightarrow{{SOC{l_2}}}B\xrightarrow{{N{H_3}}}C\xrightarrow[{B{r_2}}]{{NaOH}}D$
$\mathrm{HX}(\mathrm{aq}) \rightleftharpoons \mathrm{H}^{+}(\mathrm{aq})+\mathrm{X}(\mathrm{aq}), \mathrm{Ka}=1.2 \times 10^{-5}$
$\left[\mathrm{K}_{\mathrm{n}}:\right.$ dissociation constant]
The osmotic pressure of $0.03 \mathrm{M}$ aqueous solution of $\mathrm{HX}$ at $300 \mathrm{~K}$ is ............... $\times 10^{-2}$ bar (nearest integer).
$\left[\right.$ Given : $\mathrm{R}=0.083 \mathrm{~L} \mathrm{bar} \mathrm{Mol}^{-1} \mathrm{~K}^{-1}$ ]
${K}_2 \mathrm{Cr}_2 \mathrm{O}_7$ & ${CuSO}_4$
SideX $SPM$ Side $\mathrm{Y}$ Due to osmosis :
$(1)$ Reaction of gold with aqua regia produces $NO _2$ in the absence of air
$(2)$ Aqua regia is prepared by mixing conc. $HCl$ and conc. $HNO _3$ in $3: 1$ ($v/v$) ratio
$(3)$ Reaction of gold with aqua regia produces an anion having $Au$ in +$3$ oxidation state
$(4)$ The yellow colour of aqua regia is due to the presence of $NOCl$ and $Cl _2$