MCQ
Boolean relation at the output stage$-Y$ for the following circuit is
- A$A+B$
- B$\overline{\mathrm{A}}+\overline{\mathrm{B}}$
- ✓$\overline{\mathrm{A}}\cdot \overline{\mathrm{B}}$
- D$A \cdot B$
✓
Answer
Correct option: C.
$\overline{\mathrm{A}}\cdot \overline{\mathrm{B}}$
c
$\begin{array}{|c|c|c|}\hline A & {B} & {Y} \\ \hline 0 & {0} & {1} \\ \hline 1 & {0} & {0} \\ \hline 0 & {1} & {0} \\ \hline 1 & {1} & {0} \\ \hline\end{array}$
$\begin{array}{|c|c|c|}\hline A & {B} & {Y} \\ \hline 0 & {0} & {1} \\ \hline 1 & {0} & {0} \\ \hline 0 & {1} & {0} \\ \hline 1 & {1} & {0} \\ \hline\end{array}$
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