MCQ
Boric acid is an acid because its molecule.
- AContains replaceable $H^+$ ion.
- BGives up a proton.
- ✓Accepts $OH^-$ from water releasing proton.
- DCombines with proton from water molecule.

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$A$. Compound ' $B$ ' is aromatic
$B$. The completion of above reaction is very slow
$C$. '$A$' shows tautomerism
$D$. The bond lengths $C - C$ in compound $B$ are found to be same
Choose the correct answer from the options given below :
$C{H_3} - \mathop {\mathop {N\, - \,}\limits_{|\,\,\,\,\,\,} }\limits_{C{H_3}} \mathop {\mathop {C\,\,\, - }\limits_{|\,\,\,\,\,\,\,}^{|\,\,\,\,\,\,\,} }\limits_{{C_2}{H_5}}^{C{H_3}} C{H_2} - C{H_3}$
$(C-H= 414; H-O = 463; H-Cl=431;$$ C-Cl=326, C-O=335)$
$CH_3-OH(g) + HCl(g) \rightarrow CH_3-Cl(g) + H_2O(g)$
Compare the bond lengths $a$ and $b$