MCQ
Boron form covalent compound due to
- AHigher ionization energy
- BLower ionization energy
- CSmall size
- ✓Both $(a)$ and $(c)$
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${C_6}{H_6}\left( l \right) + \frac{{15}}{2}{O_2}\left( g \right) \longrightarrow 6C{O_2}\left( g \right) + 3{H_2}O\left( l \right)\,;\,\Delta H = - 3271\,kJ$
What is $\Delta U$ for the combustion of $1.5\, mole$ of benzene at $27\,^oC$. .....$ kJ$
Given : $K_f (H_2O)$ = $2\ K\ kg\ mole^{-1}$, $K_{sp} (PbCl_2)$ = $4 × 10^{-6}$
(Assume molarity to be equal to molality) .....$^oC$
$N_{2(g)} + O_{2(g)} \rightleftharpoons 2NO_{(g)}$ is $K,$ the equilibrium constant for $\frac{1}{2} N_{2(g)} + \frac{1}{2} O_{2(g)} \rightleftharpoons NO_{(g)}$ will be