Question
$\mathrm{Br}_2+2 \mathrm{Cl}^{-} \rightarrow \mathrm{Cl}_2+2 \mathrm{Br}^{-}$,
will this reaction take place or not?$\text{E}^0_\frac{\text{Br}_2}{\text{Br}^-}=+1.09\text{V}$
$\text{E}^0_\frac{\text{Cl}_2}{\text{Cl}^-}=+1.36\text{V}$

Answer

$\text{E}^0_\text{cell}=\text{E}^0_\frac{\text{Br}_2}{\text{Br}^-}-\text{E}^0_\frac{\text{Cl}_2}{\text{Cl}^-}$
$=1.09\text{V}-1.36$
$=-0.27\text{V}$
Since $\text{E}^0$ cell is -ve, reaction will not take place.

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