\(\Delta H=30 \mathrm{kJ} / \mathrm{mol}\)
\(\Delta S=105 J K^{-1} \mathrm{mol}^{-1}\)
For at equilibrium \(\Delta G=0\)
\(\therefore \Delta G=\Delta H-T \Delta S\)
\(\Delta H=T \Delta S\)
\(T=\frac{\Delta H}{\Delta S}=\frac{30 \times 1000 J \mathrm{mol}-1}{105 \mathrm{JK}^{-1} \mathrm{mol}^{-1}}=285.7 \mathrm{K}\)