$\therefore \,\,\Delta G\,\, = \,\,\Delta H - T\Delta S\,\,\,\,\,\therefore \,\,\,0\,\, = \,\,\Delta H\, - \,T\Delta S\,\,\,\,\therefore \,\,\Delta H\,\, = \,\,T\Delta S$
$\therefore \,\,\,\,T\,\, = \,\,\frac{{\Delta H}}{{\Delta S}}\,\, = \,\,\frac{{30 \times {{10}^3}}}{{105}}\,\, = \,\,285.7\,K$
$(I)\, q + W \,\,(II)\, q \,\,(III) \,W \,\,(IV)\, H - TS$
${C_p}$ of ${H_2}{O_{\left( g \right)}}$ $ = 33.58\,J\,{K^{ - 1}}\,mo{l^{ - 1}}$
${C_p}$ of ${H_{2\left( g \right)}}$ $ = 28.84\,J\,{K^{ - 1}}\,mo{l^{ - 1}}$
${C_p}$ of ${O_{2\left( g \right)}}$ $ = 29.37\,J\,{K^{ - 1}}\,mo{l^{ - 1}}$
${H_2}C = C{H_2}(g) + {H_2}(g) \to {H_3}C - C{H_3}(g)$
$\Delta_{f} {H}^{\ominus}$ ${KCl}=-436.7 \,{~kJ}\, {~mol}^{-1}$
$\Delta_{\text {sub }} {H}^{\ominus}$ ${K}=89.2 \,{~kJ}\, {~mol}^{-1}$
$\Delta_{\text {ionization }} \,{H}^{-}$ ${K}=419.0\, {~kJ}\, {~mol}^{-1}$
$\Delta_{\text {electron gain }} {H}^{\ominus}$ ${Cl}_{(\text {e) }}=-348.6 \,{~kJ} \,{~mol}^{-1}$
$\Delta_{{bond}} {H}^{-}$ ${Cl}_{2}=243.0 \,{~kJ} \,{~mol}^{-1}$
${KCl}$ની લેટિસ એન્થાલ્પીની તીવ્રતા $.....$ ${kJ} {mol}^{-1}$ છે.