$\begin{align}
& Ca{{C}_{2}}+2{{H}_{2}}O\xrightarrow{{}}{{C}_{2}}{{H}_{2}}+Ca{{(OH)}_{2}}\,\\ \end{align}$
$\begin{align} & \underset{\text{Acetylene}}{\mathop{{{C}_{2}}{{H}_{2}}}}\,\underset{{{60\,}^{o}}C}{\mathop{\xrightarrow{dil.\,{{H}_{2}}S{{O}_{4}}/HgS{{O}_{4}}}}}\,\underset{{}}{\mathop{[C{{H}_{2}}=CHOH]}}\,\to \underset{\text{Acetaldehyde}}{\mathop{C{{H}_{3}}CHO}}\, \\
\end{align}$
$CH_3 - CH = CH - CH_3 \xrightarrow{{{O_3}}} A $$\xrightarrow[{Zn}]{{{H_2}O}} B.$
$(1)\,CH_3C \equiv C - CH_3$ $(2)\,CH_3CH_2 -CH_2 -CH_3$
$(3)\, CH_3CH_2C \equiv CH$ $(4)\, CH_3CH = CH_2$
