\(\begin{align}
& Ca{{C}_{2}}+2{{H}_{2}}O\xrightarrow{{}}{{C}_{2}}{{H}_{2}}+Ca{{(OH)}_{2}}\,\\ \end{align}\)
\(\begin{align} & \underset{\text{Acetylene}}{\mathop{{{C}_{2}}{{H}_{2}}}}\,\underset{{{60\,}^{o}}C}{\mathop{\xrightarrow{dil.\,{{H}_{2}}S{{O}_{4}}/HgS{{O}_{4}}}}}\,\underset{{}}{\mathop{[C{{H}_{2}}=CHOH]}}\,\to \underset{\text{Acetaldehyde}}{\mathop{C{{H}_{3}}CHO}}\, \\
\end{align}\)
$\mathop {C{H_3} - }\limits_\delta \mathop {C{H_2} - }\limits_\gamma \mathop {CH = }\limits_\beta \mathop {C{H_2}}\limits_\alpha $
$(E)$
ઉપરોક્ત પ્રકિયા માં નીપજ શું હશે ?