\(56 \, g CaO \longrightarrow \Delta H =464.8 \, kJ\)
\(\therefore 233 \, g CaO \longrightarrow \Delta H =(?)\)
\(=\frac{-233 \times 164.8}{56}\)
\(=1934\, kJ\)
આપેલ : $\Delta H ^{\circ}=-54.07\,kJ\,mol ^{-1}$
$\Delta S ^{\circ}=10\,J\,K ^{-1}\,mol ^{-1}$
$(2.303 \times 8.314 \times 298=5705$ લો.)
$CO_{2(g)}$ અને $H_2O$ ના $\Delta H_f$ અનુક્રમે $-395$ અને $ -286$ $kJ \,mol^{-1}$ છે........$KJ$