Calculate the amount of charge flowing in $2$ minutes in a wire of resistance $10$ $\Omega$ when a potential difference of $20\,V$ is applied between its ends ............ $C$
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(b) $i = \frac{V}{R} = \frac{Q}{t} \Rightarrow Q = \frac{{Vt}}{R} = \frac{{20 \times 2 \times 60}}{{10}} = 240\,C$.
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