Find the number of photons emitted per second from of source of light which results in a photocurrent with drift velocity of 1.5 m/s in

Q: Find the number of photons emitted per second from of source of light which results in a photocurrent with drift velocity of $1.5\ m/s$ in a conductor with cross-section area $0.25\ m^2$ , volume density of electrons $10^{20}\ per \ m^3$ , (Assume that $60\%$ of photons emitted result in electron emission)

a $ \mathrm{i}=\mathrm{neAV}_{\mathrm{d}} $ $ \Rightarrow \frac{{{{\rm{n}}_{\rm{e}}} \times {\rm{e}}}}{{\rm{t}}} = {10^{20}} \times 1.6 \times {10^{ - 19}} \times 0.25 \times 1.5$ $= 16 \times \frac{1}{4} \times \frac{3}{2}=6 $ $ \Rightarrow \frac{\mathrm{n}_{e}}{\mathrm{t}}=\frac{6}{1.6 \times 10^{-19}} $ $ \Rightarrow \frac{{{{\rm{n}}_{\rm{p}}}}}{{\rm{t}}} = 6.25 \times {10^{19}}\,$ [ Given ${{\rm{ }}\frac{{{{\rm{n}}_{\rm{p}}}}}{{\rm{t}}} \times 60\% = \frac{{{{\rm{n}}_{\rm{e}}}}}{{\rm{t}}}}$]

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Find the number of photons emitted per second from of source of light which results in a photocurrent with drift velocity of $1.5\ m/s$ in a conductor with cross-section area $0.25\ m^2$ , volume density of electrons $10^{20}\ per \ m^3$ , (Assume that $60\%$ of photons emitted result in electron emission)

A$6.25 \times 10^{19}$
B$6.25 \times 10^{20}$
C$6 \times 10^{19}$
D$6 \times 10^{20}$

Medium

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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