Calculate the frequency of the second harmonic formed on a string of length $0.5 m$ and mass $2 × 10^{-4}$ kg when stretched with a tension of $20 N$ .... $Hz$
Medium
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(d) Mass per unit length $m = \frac{{2 \times {{10}^{ - 4}}}}{{0.5}}kg/m$
$ = 4 \times {10^{ - 4}}kg/m$
Frequency of $2^{nd}$ harmonic ${n_2} = 2{n_1}$
$ = 2 \times \frac{1}{{2l}}\sqrt {\frac{T}{m}} $$ = \frac{1}{{0.5}}\sqrt {\frac{{20}}{{4 \times {{10}^{ - 4}}}}} = 447.2Hz$
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