Calculate the mass of potassium sulphate required to prepare its $10 \%$ solution in $100\ g$ of water.
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The mass of Potassium Sulphate required to prepare its ten percent $(10 \%)$ solution in hundred gram $(100\ g)$ of water is $11.11\ g$.
Explanation: Formula: $\frac{\text{mass of solute}}{\text{mass of solution}}\times100$ A $10 \%$ mass solution in $100\ g$ of water means
$\frac{\text{x}}{(100+\text{x})}=\frac{1}{10}$ where $x$ = mass required.
$100 + x = 10x\ 100 = 9x$ $\text{x}=\frac{100}{9}=11.11\text{g}$
Explanation: Formula: $\frac{\text{mass of solute}}{\text{mass of solution}}\times100$ A $10 \%$ mass solution in $100\ g$ of water means
$\frac{\text{x}}{(100+\text{x})}=\frac{1}{10}$ where $x$ = mass required.
$100 + x = 10x\ 100 = 9x$ $\text{x}=\frac{100}{9}=11.11\text{g}$
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