Question
Calculate the oxidation number of underlined atoms.
HNO3
HNO3
✓
Answer
$HNO _3$
Oxidation number of $H =+1$
Oxidation number of $O =-2$
$HNO _3$ is a neutral molecule.
$\therefore$ Sum of the oxidation numbers of all atoms of $HNO _3=0$
$\therefore$ (Oxidation number of $H )+($ Oxidation number of $N )+3 \times($ Oxidation number of $O )=0$
$\therefore(+1)+$ (Oxidation number of $N)+3 \times(-2)=0$
$\therefore$ Oxidation number of $N +1-6=0$
$\therefore$ Oxidation number of $N$ in $HNO _3=+5$
Oxidation number of $H =+1$
Oxidation number of $O =-2$
$HNO _3$ is a neutral molecule.
$\therefore$ Sum of the oxidation numbers of all atoms of $HNO _3=0$
$\therefore$ (Oxidation number of $H )+($ Oxidation number of $N )+3 \times($ Oxidation number of $O )=0$
$\therefore(+1)+$ (Oxidation number of $N)+3 \times(-2)=0$
$\therefore$ Oxidation number of $N +1-6=0$
$\therefore$ Oxidation number of $N$ in $HNO _3=+5$
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