Question
Calculate the value of $x$ in the given figure.

Answer

Produce $CD$ to cut $AB$ at $E$.
 
Now, in $\triangle\text{BDE},$
we have, Exterior $\angle\text{"CDB}=\angle\text{CEB}+\angle\text{DBE}$
$\Rightarrow\text{x}^\circ=\angle\text{CEB}+45^\circ\ ....(\text{i)}$ In
$\triangle\text{AEC}$ we have, Exterior $\angle\text{CEB}=\angle\text{CAB}+\angle\text{ACE}$
$55^\circ+30^\circ=85^\circ$ Putting $\angle\text{CEB}=85^\circ$ in $(i)$,
we get, $\text{x}^\circ=85^\circ+45^\circ=130^\circ$
 $\therefore\text{x}=130$

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