Download App

-p-Block elements - I — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry-p-Block elements - I1 Mark
MCQ
Carbongene has $X\%$ of $CO_2$ and is used as an antidote for poisoning of $Y.$ Then, $X$ and $Y$ are
  • A
    $X = 95\%$ and $Y =$ lead poisoning
  • ✓
    $X = 5\%$ and $Y = CO$ poisoning
  • C
    $X = 30\%$ and $Y = CO_2$ poisoning
  • D
    $X = 45\%$ and $Y = CO$ poisoning
✓

Answer

Correct option: B.
$X = 5\%$ and $Y = CO$ poisoning
b
A carbongene mixture of $95\, \%$ oxygen and $5 \,\%$ carbon dioxide can be used as an antidote in $CO$ poisoning and artificial respiration in case of pneumonia patients.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from -p-Block elements - I→-p-Block elements - I — all question types→Chemistry STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

In the following which one have zero dipole moment
→
Identify the product $A$ and product $B$ in the following set of reactions.
→
Which of the following exists as a liquid at room temperature due to the formation of associated molecules only?
→
Match List$-I$ with List$-II.$

List$-I$ List$-II$
$(a)$ $Ne _{2}$ $(i)$ $1$
$(b)$ $N _{2}$ $(ii)$ $2$
$(c)$ $F _{2}$ $(iii)$ $0$
$(d)$ $O _{2}$ $(iv)$ $3$

Choose the correct answer from the options given below:

→
The dissociation of $SO_3(g)$ into $SO_2(g)$ & $O_2(g)$ is carried out in a closed container at a constant temperature $T$ . The equilibrium constant for the reaction is $K_P$ = $x\  atm^2$ . The partial pressure variation for the three gases is as shown 

The value of $x$ is

→
Which of the following elements has the highest ionization energy?
→
For per gram of reactant, the maximwn quantity of $N_2$ gas is produced in which of the following thermal decomposition reactions? (Given: Atomic wt. : $Cr\, = 52\, u, Ba\, = 137\, u$).
→
If $H ^{+}+ OH ^{-} \rightarrow H _2 O +57.32 kJ$ then to neutralise 1 mole HCl by 1 mole NaOH , the heat evolve will be :
→
In the reaction product $D$ is $\begin{array}{*{20}{c}}
  {C{H_2}} \\ 
  {||\,\,\,\,\,\,\,\,} \\ 
  {C{H_2}} 
\end{array}$ $\xrightarrow{{B{r_2}/CC{l_4}}}A\xrightarrow{{KCN}}B\xrightarrow{{{H_3}{O^ + }}}C\xrightarrow{\Delta }D$
→
The ionic radii of $O _{2}- F ^{-}, Na ^{+}$ and $Mg ^{2+}$ are in the order :
→