MCQ
$CH_2=CH-CH_3 + HBr \to ?$ What will be the product formed?
  • $\begin{array}{*{20}{c}}
      {C{H_3} - CH - C{H_3}} \\ 
      {\,|\,\,\,\,\,\,} \\ 
      {\,\,\,\,Br\,\,\,\,\,\,} 
    \end{array}$
  • B
    $\begin{array}{*{20}{c}}
      {Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {C{H_2} - C{H_2} - C{H_3}} 
    \end{array}$
  • C
    $\begin{array}{*{20}{c}}
      {C{H_2} = CH - C{H_2}} \\ 
      {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,} \\ 
      {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\,} 
    \end{array}$
  • D
    $\begin{array}{*{20}{c}}
      {CH = CH - C{H_3}\,\,\,} \\ 
      {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
    \end{array}$

Answer

Correct option: A.
$\begin{array}{*{20}{c}}
  {C{H_3} - CH - C{H_3}} \\ 
  {\,|\,\,\,\,\,\,} \\ 
  {\,\,\,\,Br\,\,\,\,\,\,} 
\end{array}$
a

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