MCQ
$C{H_3} - CH = C{H_2}\xrightarrow[{(low\,\,conc.)}]{{B{r_2}/hv}}(A)$ ; Product $(A)$ of the reaction is
- A$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - Br}\\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ - ✓$H_2C = CH - CH_2 -Br$
- C$\begin{array}{*{20}{c}}
{C{H_3} - C = C{H_2}}\\
|\\
{\,\,\,Br}
\end{array}$ - D$Br - CH_2 - CH_2 - CH_2 -Br$
