MCQ
What will be $\Delta S$ for reaction: $2A + 3B \to 4C + 5D$

$\Delta S_A^o = 100\frac{J}{{mol \times k}}$   $\Delta S_C^o = 200\frac{J}{{mol \times k}}$

$\Delta S_B^o = 120\frac{J}{{mol \times k}}$   $\Delta S_D^o = 150\frac{J}{{mol \times k}}$

  • A
    $150\,\frac{J}{k}$
  • $990\,\frac{J}{k}$
  • C
    $300\,\frac{J}{k}$
  • D
    $130\,\frac{J}{k}$

Answer

Correct option: B.
$990\,\frac{J}{k}$
b
$\Delta \mathrm{S} =\sum(\mathrm{S})_{\mathrm{products}} \quad \sum(\mathrm{S})_{\mathrm{ractant} \mathrm{s}} $

$=4 \times 200+5 \times 150-(100 \times 2+3 \times 120) $

$=800+750-560 $

$=990\, \mathrm{J} / \mathrm{k} $

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free