MCQ
$C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C\equiv CH+\underset{\begin{smallmatrix} 
 Lithium\, \\ 
 amide 
\end{smallmatrix}}{\mathop{LiN{{H}_{2}}}}\,\to (A)\xrightarrow{{{(C{{H}_{3}})}_{2}}S{{O}_{4}}}(B)$

Give the structural formula of compound $(B)$

  • A
    $CH_3 -(CH_2)_2 - C \equiv C -SO_3H$
  • $CH_3 - (CH_2)_2 - C \equiv C -CH_3$
  • C
    $C{{H}_{3}}-{{(C{{H}_{2}})}_{2}}-C\equiv C-C{{H}_{2}}-\begin{matrix}
       O  \\
       ||  \\
       O-S-H  \\
       ||  \\
       O  \\
    \end{matrix}$
  • D
    $CH_3 -CH_2 - C \equiv C - CH_2$

Answer

Correct option: B.
$CH_3 - (CH_2)_2 - C \equiv C -CH_3$
b

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