\(C{{H}_{3}}-C{{H}_{2}}-C\equiv N\) \(\xrightarrow{{SnC{l_2}\,/\,HCl}}\) \(C{H_3}C{H_2}CH = NH\)
\(\xrightarrow[{(Ether)}]{{{H_2}O\,,\,boil}}\) \(C{H_3}C{H_2}CHO\, + \,N{H_4}Cl\)
It is stephen's reduction.
ઉપરોક્ત પ્રક્રિયા કઇ પરીસ્થિતીમા થાય છે ?
$(1)$ $\begin{matrix}
O \\
|| \\
{{C}_{6}}{{H}_{5}}-C-{{C}_{6}}{{H}_{5}} \\
\end{matrix}$
$(2)$ $C _{6} H _{5}- CHO$
$(3)$ $p - CH _{3}- C _{6} H _{4}- CHO$
$(4)$ $p - CH _{3} O - C _{6} H _{4}- CHO$
$\mathop {\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_2} = C - C{H_2} - C - C{H_3}}
\end{array}}\limits_{(I)} \rightleftharpoons $
$\mathop {\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C - C{H_2} - C - C{H_3}}
\end{array}}\limits_{(II)} \rightleftharpoons $
$\mathop {\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C = CH - C - C{H_3}}
\end{array}}\limits_{(III)} $
$\mathop {(A)}\limits_{ gives\,\,positive ~\\ iodoform\,Test } \xrightarrow[\begin{subarray}{l} (ii)\,{H^ + },{H_2}O + ~\\ (iii)\,conc.\,{H_2}S{O_4}/\Delta \end{subarray} ]{{{\text{(i) C}}{{\text{H}}_{\text{3}}}{\text{MgBr}}}}(B)\xrightarrow{{{O_3}/Zn,{H_2}O}}$