Febling-solution and Benedict solution. These reagents cannot be used to distinguish them
\(C H_{3} C H O\) reacts with \(N a O H\) and \(I_{2}\) to form yellow crystalline iodoform while \(C_{6} H_{5} C H_{2} C H O\)
does not react with it. \(\mathrm{CH}_{3} \mathrm{CHO}+3 \mathrm{I}_{2}+4 \mathrm{NaOH} \longrightarrow \)\(\mathrm{CHI}_{3}\) (Yellow crystalline ppt) \( +3 \mathrm{NaI}+3 \mathrm{H}_{2} \mathrm{O}\)
\(C_{6} H_{5} C H_{2} C H O+3 I_{2}+4 N a O H \rightarrow N\) oreaction
\(\therefore\) lodoform test can be used to distinguish between \(C H_{3} C H O\) and \(C_{6} H_{5} C H_{2} C H O\)
$[Figure]$ $\xrightarrow[{{\text{AlC}}{{\text{l}}_3}}]{{{\text{Succinic anhydride}}}}A\xrightarrow[{{\text{reduction}}}]{{{\text{Clemmenson 's}}}}X$ શું હશે ?
$HC \equiv CH\mathop {\xrightarrow{{30\%\, {H_2}S{O_4}}}}\limits_{HgS{O_4}} A\xrightarrow{{NaOH}}B$

ઉપરના વિધાનોના સંદર્ભ માં નીચે આપેલા વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો.


$R - C \equiv N\xrightarrow[{(2)\,{H_2}O}]{{(1)\,AlH\,{{(i - Bu)}_2}}}$ ?