MCQ
$C{H_4}$ is formed when
- ASodium acetate is heated with sodalime
- BIodomethane is reduced
- CAluminium carbide reacts with water
- ✓All of these
$\mathop {C{H_3}I}\limits_{{\rm{Iodomethane}}} + 2H \xrightarrow[Reduction] C{H_4} + HI$
$\mathop {A{l_4}{C_3} + 6{H_2}O}\limits_{{\rm{Aluminium}}\,{\rm{carbide}}} \to 3C{H_4} + 2A{l_2}{O_3}$
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$A.$ $I _2( g ) \rightarrow 2 I ( g )$
$B.$ $HCl ( g ) \rightarrow H ( g )+ Cl ( g )$
$C.$ $H _2 O ( l ) \rightarrow H _2 O ( g )$
$D.$ $C ( s )+ O _2( g ) \rightarrow CO _2( g )$
$E.$ Dissolution of ammonium chloride in water
$NH_4HS(s) \rightleftharpoons NH_3(g)+H_2S(g)$
is following to set up at $127\,^oC$ in a closed vessel. The total pressure at equilibrium was $20\,atm$ . The $K_C$ for the reaction is
Statement $I:$ Upon heating a borax bead dipped in cupric sulphate in a luminous flame, the colour of the bead becomes green.
Statement $II:$ The green colour observed is due to the formation of copper(I) metaborate.
In the light of the above statements, choose the most appropriate answer from the options given below :
true about this mechanism