MCQ
Choose the correct answer from the given four options : A mason constructs a wall of dimensions $270\ cm \times 300\ cm \times 350\ cm$ with the bricks each of size $22.5\ cm \times 11.25\ cm \times 8.75\ cm$ and it is assumed that $\frac{1}{8}$ space is covered by the mortar. Then the number of bricks used to construct the wall is :
  • A
    $11100$
  • $11200$
  • C
    $11000$
  • D
    $11300$

Answer

Correct option: B.
$11200$
Volume of the wall $= 270 \times 300 \times 350=28350000 \mathrm{~cm}^3$
$[\because$ volume of chboid $=$ lenth $\times$ breadth $\times $ height$]$
Since, $\frac{1}{8}$ space of wall is covered by mortar.
So, remainig space of wall $=$ Volume of wall $-$ Volume of mortar
$=28350000-28350000\times\frac{1}{8}$
$=28350000-3543750=24806250\text{ cm}^3$
Now, volume of one birck $= 22.5 \times 1125 \times 875 = 2214.844\ cm3$
$[\because$ volume of chboid $=$ lenth $\times $ breadth $\times $ height$]$
$\therefore$ Required number of bricks $=\frac{24806250}{2214.844}=11200\ (\text{approx})$
Hence, the number of used to construct the wall is $11200.$

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