MCQ
Choose the correct answer.
If |x - 1| > 5, then:
If |x - 1| > 5, then:
- A$\text{x}\in(-4, 6)$
- B$\text{x}\in[-4,6]$
- C$\text{x}\in[-\infty,-4)\cup(6,\infty) $
- D$\text{x}\in[-\infty,-4)\cup[6,\infty) $
Solution:
Given that |x - 1| > 5
⇒ (x - 1) < -5 or (x - 1) > 5
⇒ x < -5 + 1 or x > 5 + 1
⇒ x < -4 or x > 6
$\Rightarrow\text{x}\in[-\infty,-4)\cup(6,\infty) $
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