MCQ
Complete the reaction: 
86​Rn22084​Po216+ __________:
  • A
    $\beta$
  • B
    $\gamma$
  • C
    $\alpha$
  • D
    $\text{H}^1_1$

Answer

  1. $\alpha$

Explanation:

86​Rn220 → 84​Po216 Z​XA

Z + 84 = 86 and 220 = 216 + A

So, Z = 2 and A = 4

$2​​\alpha^4$

So, it is $\alpha$ particle.

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