MCQ
Consider a circular loop that is uniformly charged and has a radius $\mathrm{a} \sqrt{2}$. Find the position along the positive z - axis of the cartesian coordinate system where the electric field is maximum if the ring was assumed to be placed in xy - plane at the origin :
  • A
    $\frac{\mathrm{a}}{\sqrt{2}}$
  • B
    $\frac{a}{2}$
  • C
    a
  • D
    $0$

Answer

C. a
$E=\frac{K Q r}{\left(x^{2}+R^{2}\right)^{3 / 2}}$
$\frac{\mathrm{dE}}{\mathrm{dx}}=0$
$\therefore \mathrm{x}=\frac{\mathrm{R}}{\sqrt{2}}=\frac{\sqrt{2} \mathrm{a}}{\sqrt{2}}=\mathrm{a}$

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