Question
Consider an electron in a hydrogen atom, revolving in its second excited state (having radius $4.65\, \mathop A\limits^o $). The de-Broglie wavelength of this electron is....$\mathop A\limits^o $
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Answer
$2 \pi r_{n}=n \lambda_{n}$
$\lambda_{3}=\frac{2 \pi\left(4.65 \times 10^{-10}\right)}{3}$
$\lambda_{3}=9.7 \mathrm{A}$
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