MCQ
Consider the following processes :

  $\Delta H \,(kJ/mol)$
$\frac 12 A \rightarrow B$ $+150$
$3B \rightarrow 2C + D$ $-125$
$E + A \rightarrow 2D$ $+350$

For $B + D \rightarrow E + 2C, \Delta H$ will be ............. $\mathrm{kJ/mol}$

  • A
    $525$
  • $-175$
  • C
    $-325$
  • D
    $325$

Answer

Correct option: B.
$-175$
b
$2(i)-(i i i)+(i i)$

$\Delta H=2(150)-350-125$

$=-175 \mathrm{kJ} / \mathrm{mol}$

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