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6.1. Equilibrium - 1 (chemical Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.1. Equilibrium - 1 (chemical Equilibrium)1 Mark
MCQ
For the reaction $PC{l_3}_{(g)} + C{l_2}_{(g)}$ $\rightleftharpoons$ $PC{l_5}_{(g)}$ at ${250\,^o}C$, the value of ${K_c}$ is $26$, then the value of ${K_p}$ on the same temperature will be
  • ✓
    $0.61$
  • B
    $0.57$
  • C
    $0.83$
  • D
    $0.46$
✓

Answer

Correct option: A.
$0.61$
(a) ${K_p} = {K_c}{(RT)^{\Delta n}}$$ = 26\,{(0.0821 \times 523)^{ - 1}} = 0.61$.

$\Delta {n_g} = 1 - 2 = - 1$

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