- ACase (i) contradicts Gauss’s law for electrostatic fields.
- BCase (ii) contradicts Gauss’s law for magnetic fields.
- CCase (i) agrees with $\oint\text{E.dl=0.}$
- DCase (ii) contradict $\oint\text{H.dl}=\text{I}_\text{en}$.
Solution:
Key concept: The electrostatic field lines, do not form a continuous closed path (this follows from the conservative nature of electric field) while the magnetic field lines form the closed paths.
According to the Gauss' law, $\oint\text{E.ds}=\frac{\text{q}}{\in_0}$ for electronstatic field. It does not contradict foe eletrostatic fields as the elecric field lines do not form a continuous closed path.
According to Gauss' law in magnetism.
$\oint\text{B.ds}=0$
Which implies that number of magnetic field lines entering the Gaussian surface is equal to the number of magnetic field lines leaving it. Therefore case (ii) is not possible.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Approximate height of ozone layer above the ground is
|
(a) 60 to 70 km |
(b) 59 km to 80 km |
(c) 70 km to 100 km |
(d) 100 km to 200 km |
Lenz's law is consequence of the law of conservation of
|
(a) Charge |
(b) Momentum |
(c) Mass |
(d) Energy |
In the circuit shown P ≠ R, the reading of the galvanometer is same with switch S open or closed. Then
|
(a) |
(b) |
(c) |
(d) |