Consider two rods of same length and different specific heats $\left(S_{1}, S_{2}\right)$, conductivities $\left(K_{1}, K_{2}\right)$ and area of cross-sections $\left(A_{1}, A_{2}\right)$ and both having temperatures $T_{1}$ and $T_{2}$ at their ends. If rate of loss of heat due to conduction is equal, then
  • A${K_1}{A_2} = {K_2}{A_1}$
  • B${K_1}{A_1} = {K_2}{A_2}$
  • C${K_1} = {K_2}$
  • D${K_1}A_1^2 = {K_2}A_2^2$
AIPMT 2002, Medium
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