Question
Construct a parallelogram $ABCD$ in which $AB = 5.2\ cm, BC = 4.7\ cm$ and $AC = 7.6\ cm$
✓
Answer
Steps of construction:
Step 1: Draw $AB = 5.2\ cm.$
Step 2: With $B$ as the centre, draw an arc of $4.7\ cm.$
Step 3: With $A$ as the centre, draw another arc of $7.6\ cm,$ cutting the previous arc at $C.$
Step 4: Join $A$ and $C.$
Step 5: We know that the opposite sides of a parallelogram are equal. Thus, with $C$ as the centre, draw an arc of $5.2\ cm.$
Step 6: With $A$ as the centre, draw another arc of $4.7\ cm,$ cutting the previous arc at $D.$
Step 7: Join $CD$ and $AD.$
Then, $ABCD$ is the required parallelogram.
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