Question
Construct a parallelogram $\text{POUR}$ in which, $\text{PO}=5.5\ cm, \text{OU} = 7.2\ cm$ and $\angle\text{O}=70^\circ.$
✓
Answer
Since, opposite sides of a parallelogram are equal.
$\therefore$ $\text{PO = RU} = 5.5\ cm, \text{OU = RP} = 7.2\ cm.$
Steps of Construction:
$1.$ Draw $\text{PO} = 5.5\ cm$.
$2.$ Construct $\angle\text{POX}=70^\circ.$
$3.$ With $O$ as centre $\&$ radius $\text{OU} = 7.2\ cm$, draw an arc.
$4.$ With centre $U\ \&$ radius $\text{UR} = 5.5\ cm$, draw an arc
$5.$ With $P$ as centre $\&$ radius $\text{PR} = 7.2\ cm$, draw an arc to cut the arc drawn in Step $4$.
$6.$ Now, Join $\text{PR}$ and $\text{UR}$.
Hence, $\text{POUR}$ is the required parallelogram.
$\therefore$ $\text{PO = RU} = 5.5\ cm, \text{OU = RP} = 7.2\ cm.$
Steps of Construction:
$1.$ Draw $\text{PO} = 5.5\ cm$.
$2.$ Construct $\angle\text{POX}=70^\circ.$
$3.$ With $O$ as centre $\&$ radius $\text{OU} = 7.2\ cm$, draw an arc.
$4.$ With centre $U\ \&$ radius $\text{UR} = 5.5\ cm$, draw an arc
$5.$ With $P$ as centre $\&$ radius $\text{PR} = 7.2\ cm$, draw an arc to cut the arc drawn in Step $4$.
$6.$ Now, Join $\text{PR}$ and $\text{UR}$.
Hence, $\text{POUR}$ is the required parallelogram.
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