Question
Construct a parallelogram $PQRS$ such that $PQ = 5.2\ cm, PR = 6.8\ cm$ and $QS = 8.2\ cm$.
✓
Answer
In a parallelogram opposite sides are equal.
Thus, we have to construct a quadrilateral $PQRS$ in which $PQ = 5.2\ cm, PR = 6.8\ cm$ and $QS = 8.2\ cm$.
Steps of construction:
Step $I$: Draw $QS = 8.2\ cm$
Step $II$: With $Q$ as the centre and radius $5.2\ cm$, draw an arc.
Step $III$: With $S$ as the centre and radius $5.2\ cm$, draw an arc to intersect the arc drawn in Step $II$ at $C$.
Step $IV$: With $P$ as the centre and radius $6.8\ cm$.
Step $V$: With $Q$ as the centre and radius $5.2\ cm$, draw an arc to intersect the arc drawn in Step $IV$ at $A$.
Step $VI$: Join $QR, QP, PS$ and $SR$.
The quadrilateral $PQRS$ so obtained is the required quadrilateral.
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