Question
Construct a quadrilateral $ABCD$ in which $AB = 2.8\ cm, BC = 3.1\ cm, CD = 2.6\ cm,$ and $DA = 3.3\ cm$ and $\angle\text{A}=60^\circ.$
✓
Answer
Steps of construction:
Step $I$: Draw $AB = 2.8\ cm$.
Step $II$: Construct $\angle\text{BAD}=60^\circ.$
Step $III$: With $A$ as the centre and radius $3.3\ cm$, cut off $AD = 3.3\ cm$.
Step $IV$: With $D$ as the centre and radius $2.6\ cm$, draw an arc.
Step $V$: With $B$ as the centre and radius $3.1\ cm$, draw an arc to intersect the arc drawn in Step $IV$ at $C$.
Step $VI$: Join $BC$ and $CD$ to obtained the required quadrilateral.
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