Question
Construct a quadrilateral $ABCD$, in which $AD = 3.5\ cm, AB = 4.4\ cm, BC = 4.7\ cm$, $\angle\text{A}=125^\circ.$ and $\angle\text{B}=120^\circ.$
✓
Answer
Steps of construction:
Step $I$: Draw $QR = 2.5\ cm$.
Step $II$: Construct $\angle\text{PQr}=75^\circ$ at $Q$.
Step $III$: With $Q$ as the centre and radius $3.5\ cm$, cut off $QP = 3.5\ cm$.
Step $IV$: Construct $\angle\text{QRS}=120^\circ$ at $R$.
Step $V$: With $R$ as the centre and radius $4.1\ cm$, cut off $RS = 4.1\ cm$.
Step $VI$: Join $PS$.
The quadrilateral so obtained is the required quadrilateral.
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$(v)$
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$(f)$
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$(vi)$
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