Question
Construct a quadrilateral $\text{ABCD}$ in which $AB = 4.6\ cm, BD = 5\ cm, AC = 6\ cm, CD = 4.2\ cm$ and $\angle A = 90^\circ $
✓
Answer
$AB = 4.6\ cm, BD = 5\ cm, AC = 6\ cm, CD = 4.2\ cm$ and $\angle A = 90^\circ $
Steps of construction:
$1)$Draw a line segment $AB = 4.6\ cm$
$2)$With $A$ as centre, draw a ray making an angle of $90^\circ $ with $AB$
$3)$With $B$ as centre and radius equal to $5\ cm$ cut an arc on the ray from $A$ and mark it as $D.$
$4)$With $D$ as centre and radius $4.2\ cm$ cut an arc on right side of $AD.$
$5)$With $A$ as centre and radius $6\ cm$ cut an arc which meets the arc from $D$ at point $C.$
$6)$Join $BC.$
$7)\text{ABCD}$ is the required quadrilateral.
Steps of construction:
$1)$Draw a line segment $AB = 4.6\ cm$
$2)$With $A$ as centre, draw a ray making an angle of $90^\circ $ with $AB$
$3)$With $B$ as centre and radius equal to $5\ cm$ cut an arc on the ray from $A$ and mark it as $D.$
$4)$With $D$ as centre and radius $4.2\ cm$ cut an arc on right side of $AD.$
$5)$With $A$ as centre and radius $6\ cm$ cut an arc which meets the arc from $D$ at point $C.$
$6)$Join $BC.$
$7)\text{ABCD}$ is the required quadrilateral.
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