Question
Construct a rectangle $\text{ABCD},$ when:Area $= 24 \ cm^2$ and base $= 4.8 \ cm^2$.
✓
Answer
Given that the base $=4.8 \ cm ^2$ and Area $=24 \ cm ^2$
We know that the area of the rectangle $=$ base $\times$ Height.
Therefore,
$24=4.8 \ \times$ height
Height $=5$
With base $=4.8 \ cm ^2$ and height $=5 \ cm ^2,$
the rectangle is shown below:
Steps :
$1.$ Draw base $A B=4.8 \ cm ^2$.
$2.$ With $A$ and $B$ as a center draw an arc taking radius $5 \ cm ^2$ at $D$ and $C$.
$3.$ Now join $A D, B C$, and $D C$.
$\text{ABCD}$ is the required rectangle.
We know that the area of the rectangle $=$ base $\times$ Height.
Therefore,
$24=4.8 \ \times$ height
Height $=5$
With base $=4.8 \ cm ^2$ and height $=5 \ cm ^2,$
the rectangle is shown below:
Steps :
$1.$ Draw base $A B=4.8 \ cm ^2$.
$2.$ With $A$ and $B$ as a center draw an arc taking radius $5 \ cm ^2$ at $D$ and $C$.
$3.$ Now join $A D, B C$, and $D C$.
$\text{ABCD}$ is the required rectangle.
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