Question
Construct a right-angled triangle ABC whose base BC is 6cm and the sum of the hypotenuse AC and other side AB is 10cm.

Answer


Steps of construction:
  1. Construct a line segment BC of 6cm.
  2. At the point B, draw $\angle\text{XBC}=90^\circ.$
  3. Keeping B as center and radius 10cm draw an arc which intersects XB at D.
  4. Join DC.
  5. Draw the perpendicular bisector of DC which intersects DB at A.
  6. Join AC.
Hence $\triangle\text{ABC}$ is the required triangle.

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