Question
Construct a right$-$angled triangle in which Side $DE = 6 \ cm$ and $\angle E = 30^\circ , \angle D = 90^\circ $
✓
Answer
Steps:
$1$. Draw $DE = 6\ cm.$
$2$. At $D$, construct $\angle PDE = 90^\circ $
$3$. With $E$ as centre, draw $\angle DEM = 30^\circ $
$4$. Ray $DP$ and ray $EM$ intersect at $F.$
Thus, $\text{DEF}$ is the required triangle.
$1$. Draw $DE = 6\ cm.$
$2$. At $D$, construct $\angle PDE = 90^\circ $
$3$. With $E$ as centre, draw $\angle DEM = 30^\circ $
$4$. Ray $DP$ and ray $EM$ intersect at $F.$
Thus, $\text{DEF}$ is the required triangle.
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